I'm asked to prove $\tan \theta=\cot (90-\theta)$ So $\tan \theta =\frac{a}{b}=\cot(90^\circ-\theta)$ But what if $\theta>90?$
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Tan(90-x)=cot(x) Trigonometry, 41% OFF
I have to memorize over 30 Trigonometric identities and additional
tan(90 – x), tan(90 – A), tan(90 – theta)