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waves - Why do we demand that $\lambda \ll \text{size of slit

By A Mystery Man Writer

I'd appreciate it if anyone could explain to me why do we demand that the wavelength will be much smaller than the distances between the slits in order to see wave diffraction when performing Young's

$waves - Why do we demand that $\lambda \ll \text{size of slit$

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$waves - Why do we demand that $\lambda \ll \text{size of slit$

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$waves - Why do we demand that $\lambda \ll \text{size of slit$

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$waves - Why do we demand that $\lambda \ll \text{size of slit$

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$waves - Why do we demand that $\lambda \ll \text{size of slit$

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$waves - Why do we demand that $\lambda \ll \text{size of slit$

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$waves - Why do we demand that $\lambda \ll \text{size of slit$

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$waves - Why do we demand that $\lambda \ll \text{size of slit$

visible light - How can you show with a diagram that diffraction is at a maximum when the slit width is equal to the wavelength? - Physics Stack Exchange

$waves - Why do we demand that $\lambda \ll \text{size of slit$

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$waves - Why do we demand that $\lambda \ll \text{size of slit$

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$waves - Why do we demand that $\lambda \ll \text{size of slit$

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$waves - Why do we demand that $\lambda \ll \text{size of slit$

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